how can 0 be a repository

if you take 1 and replace it with 0 you can make a repository out of 0

01
10 <--save 0 and move it to a pile

0 <--pile zero
then take 1 and move it to another pile

1 <--pile 1
then take 0 and move it to the next position in a NEW pile

-----------------------------------------------------------------------------
__ <--transistion possible 0 <-- zero repository transition

so now we can divulge that 0 can be a formal repository

0 respose 0 repose 1 1 1
three repose 0 1 repose 1 respose 1
0 repose 1 align reposotory

alignment with 0 repository

00000000 <-- zero repository
1                 <-- one repository transistion in ZINCID plane

0 repostory 1 transition high order bit transition in respository
1 align repository 0 repose 1 order bit high in array tranistion SZ
one S or stream 1
one Z or compress respository 1sz low character bit in high order drain bit entropy field
one high entropy bit field
one low entropy bit repository
one low bit
one high bit
one high draft number
one low draft number
align low compresser aLrithm'im over time to high order bit drain low repository transition to new bit pos __aligntranistionxenundraft

in this instance a xenun draft is much like a term where the repository is a stream where the position of a bit is depending on a character array so'a in term the character array is in term symbian for xenun draft where possible'sza RARE bit/byte thqoursuse is term seliac orbein.



0 or 1
repository 01
0 orbein xenun tranistion draft aLrithm'm
0 align orbein transistion field byte culture 9cntensorsupportalign
1 orbein high order bit tranistion out of repository
0 high low order where repository is in high order where character byte culture 'a' is term or prime feedback MAL

in order M A is hive where high andject L is depth draft xenun possible transition 'a' in order repository
in M 'a' is term or where high in order characters the depth of possible transistion is in order hive shift andject  'a' ?